(1/2)(6x-4)=(3/4)(12-4x)

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Solution for (1/2)(6x-4)=(3/4)(12-4x) equation: 



(1/2)(6x-4)=(3/4)(12-4x)

We move all terms to the left:

(1/2)(6x-4)-((3/4)(12-4x))=0



Domain of the equation: 2)(6x-4)!=0

x∈R





Domain of the equation: 4)(12-4x))!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)(6x-4)-((+3/4)(-4x+12))=0

We multiply parentheses ..

(+6x^2+1/2*-4)-((+3/4)(-4x+12))=0

We calculate fractions


((+6x^2+1*4)(-4x+12)))/(-4)*4)(-4x+12))+2*)+()/(-4)*4)(-4x+12))+2*)=0

We calculate fractions


(((+6x^2+1*4)(-4x+12)))*(-4)*4)(-4x+12))+2*))/(-4x)+(-4)*4)(-4x+12))+2*)+()*()/(-4x)=0

We can not solve this equation

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