3(4z+2)=16+2(6z-5)

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Solution for 3(4z+2)=16+2(6z-5) equation: 



3(4z+2)=16+2(6z-5)

We move all terms to the left:

3(4z+2)-(16+2(6z-5))=0

We multiply parentheses

12z-(16+2(6z-5))+6=0



We calculate terms in parentheses: -(16+2(6z-5)), so:

16+2(6z-5)

determiningTheFunctionDomain
2(6z-5)+16

We multiply parentheses

12z-10+16

We add all the numbers together, and all the variables

12z+6

Back to the equation:

-(12z+6)



We get rid of parentheses

12z-12z-6+6=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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