(1/2)(2y+4)-8=(1/9)(27y-54)

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Solution for (1/2)(2y+4)-8=(1/9)(27y-54) equation: 


y in (-oo:+oo)

(1/2)*(2*y+4)-8 = (1/9)*(27*y-54) // - (1/9)*(27*y-54)

(1/2)*(2*y+4)-((1/9)*(27*y-54))-8 = 0

(1/2)*(2*y+4)+(-1/9)*(27*y-54)-8 = 0

1/2*(2*y+4)-1/9*(27*y-54)-8 = 0

1/2*(2*y+4)-1/9*(27*y-54)-8 = 0

8-2*y-8 = 0

-2*y = 0

-2*y = 0

-2*y = 0 // : -2

y = 0

y = 0

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