(7c-5)(7c+5)=0

Solution for (7c-5)(7c+5)=0 equation:

Simplifying
(7c + -5)(7c + 5) = 0

Reorder the terms:
(-5 + 7c)(7c + 5) = 0

Reorder the terms:
(-5 + 7c)(5 + 7c) = 0

Multiply (-5 + 7c) * (5 + 7c)
(-5(5 + 7c) + 7c * (5 + 7c)) = 0
((5 * -5 + 7c * -5) + 7c * (5 + 7c)) = 0
((-25 + -35c) + 7c * (5 + 7c)) = 0
(-25 + -35c + (5 * 7c + 7c * 7c)) = 0
(-25 + -35c + (35c + 49c2)) = 0

Combine like terms: -35c + 35c = 0
(-25 + 0 + 49c2) = 0
(-25 + 49c2) = 0

Solving
-25 + 49c2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 49c2 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + 49c2 = 0 + 25
49c2 = 0 + 25

Combine like terms: 0 + 25 = 25
49c2 = 25

Divide each side by '49'.
c2 = 0.5102040816

Simplifying
c2 = 0.5102040816

Take the square root of each side:
c = {-0.714285714, 0.714285714}