(1/14)(3x-4)=x+10/10

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Solution for (1/14)(3x-4)=x+10/10 equation: 



(1/14)(3x-4)=x+10/10

We move all terms to the left:

(1/14)(3x-4)-(x+10/10)=0



Domain of the equation: 14)(3x-4)!=0

x∈R



We add all the numbers together, and all the variables

(+1/14)(3x-4)-(x+1)=0

We get rid of parentheses

(+1/14)(3x-4)-x-1=0

We multiply parentheses ..

(+3x^2+1/14*-4)-x-1=0

We multiply all the terms by the denominator


(+3x^2+1-x*14*-4)-1*14*-4)=0

We add all the numbers together, and all the variables

(+3x^2+1-x*14*-4)=0

We get rid of parentheses

3x^2-x*14*+1-4=0

We add all the numbers together, and all the variables

3x^2-x*14*-3=0

Wy multiply elements

3x^2-14x^2-3=0

We add all the numbers together, and all the variables

-11x^2-3=0

a = -11; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-11)·(-3)
Δ = -132
Delta is less than zero, so there is no solution for the equation

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