7(2m-1)-(3/5)m=(6/5)(4-3m)

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Solution for 7(2m-1)-(3/5)m=(6/5)(4-3m) equation: 



7(2m-1)-(3/5)m=(6/5)(4-3m)

We move all terms to the left:

7(2m-1)-(3/5)m-((6/5)(4-3m))=0



Domain of the equation: 5)m!=0

m!=0/1

m!=0

m∈R





Domain of the equation: 5)(4-3m))!=0

m∈R



We add all the numbers together, and all the variables

7(2m-1)-(+3/5)m-((+6/5)(-3m+4))=0

We multiply parentheses

-3m^2+14m-((+6/5)(-3m+4))-7=0

We multiply parentheses ..

-3m^2-((-18m^2+6/5*4))+14m-7=0

We multiply all the terms by the denominator


-18m^2-3m^2*5*4))-((+14m*5*4))-7*5*4))+6=0

Wy multiply elements

-18m^2-60m^3*4+5600m^3*4=0

We do not support empression: m^3

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