(1-x)(x+1)=8

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Solution for (1-x)(x+1)=8 equation: 



(1-x)(x+1)=8

We move all terms to the left:

(1-x)(x+1)-(8)=0

We add all the numbers together, and all the variables

(-1x+1)(x+1)-8=0

We multiply parentheses ..

(-1x^2-1x+x+1)-8=0

We get rid of parentheses

-1x^2-1x+x+1-8=0

We add all the numbers together, and all the variables

-1x^2-7=0

a = -1; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·(-1)·(-7)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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