(1-k)(4-k)(9-k)=0

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Solution for (1-k)(4-k)(9-k)=0 equation: 



(1-k)(4-k)(9-k)=0

We add all the numbers together, and all the variables

(-1k+1)(-1k+4)(-1k+9)=0

We multiply parentheses ..

(+k^2-4k-1k+4)(-1k+9)=0

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