(9x+2)x2-8=-(9x+12)+9x

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Solution for (9x+2)x2-8=-(9x+12)+9x equation: 



(9x+2)x2-8=-(9x+12)+9x

We move all terms to the left:

(9x+2)x2-8-(-(9x+12)+9x)=0

We multiply parentheses

9x^3+2x^2-(-(9x+12)+9x)-8=0



We calculate terms in parentheses: -(-(9x+12)+9x), so:

-(9x+12)+9x

We add all the numbers together, and all the variables

9x-(9x+12)

We get rid of parentheses

9x-9x-12

We add all the numbers together, and all the variables

-12

Back to the equation:

-(-12)



We do not support expression: x^3

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