(1+x)+x=4x-2020

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Solution for (1+x)+x=4x-2020 equation: 



(1+x)+x=4x-2020

We move all terms to the left:

(1+x)+x-(4x-2020)=0

We add all the numbers together, and all the variables

(x+1)+x-(4x-2020)=0

We add all the numbers together, and all the variables

x+(x+1)-(4x-2020)=0

We get rid of parentheses

x+x-4x+1+2020=0

We add all the numbers together, and all the variables

-2x+2021=0

We move all terms containing x to the left, all other terms to the right

-2x=-2021

x=-2021/-2

x=1010+1/2

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