1+x+x=4x-2020

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Solution for 1+x+x=4x-2020 equation: 



1+x+x=4x-2020

We move all terms to the left:

1+x+x-(4x-2020)=0

We add all the numbers together, and all the variables

2x-(4x-2020)+1=0

We get rid of parentheses

2x-4x+2020+1=0

We add all the numbers together, and all the variables

-2x+2021=0

We move all terms containing x to the left, all other terms to the right

-2x=-2021

x=-2021/-2

x=1010+1/2

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