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(1+n)n=870
We move all terms to the left:
(1+n)n-(870)=0
We add all the numbers together, and all the variables
(n+1)n-870=0
We multiply parentheses
n^2+n-870=0
a = 1; b = 1; c = -870;
Δ = b2-4ac
Δ = 12-4·1·(-870)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-59}{2*1}=\frac{-60}{2} =-30 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+59}{2*1}=\frac{58}{2} =29 $
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