(1+2x)/9=1-(x+4)/6

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Solution for (1+2x)/9=1-(x+4)/6 equation: 



(1+2x)/9=1-(x+4)/6

We move all terms to the left:

(1+2x)/9-(1-(x+4)/6)=0

We add all the numbers together, and all the variables

(2x+1)/9-(1-(x+4)/6)=0

We calculate fractions


2x/()+(-(1-(x+4)*9)/()=0



We calculate terms in parentheses: +(-(1-(x+4)*9)/(), so:

-(1-(x+4)*9)/(

We multiply all the terms by the denominator


-(1-(x+4)*9)



We calculate terms in parentheses: -(1-(x+4)*9), so:

1-(x+4)*9

determiningTheFunctionDomain
-(x+4)*9+1

We multiply parentheses

-9x-36+1

We add all the numbers together, and all the variables

-9x-35

Back to the equation:

-(-9x-35)



We get rid of parentheses

9x+35

Back to the equation:

+(9x+35)



We get rid of parentheses

2x/()+9x+35=0

We multiply all the terms by the denominator


2x+9x*()+35*()=0

We add all the numbers together, and all the variables

2x+9x*()=0

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