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(1)/(9)-(2)/(3)b=(1)/(18)
We move all terms to the left:
(1)/(9)-(2)/(3)b-((1)/(18))=0
Domain of the equation: 3b!=0We add all the numbers together, and all the variables
b!=0/3
b!=0
b∈R
-2/3b+1/9-(+1/18)=0
We get rid of parentheses
-2/3b+1/9-1/18=0
We calculate fractions
There is no solution for this equation
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