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(1)/(5)(15b-7)=3b-9
We move all terms to the left:
(1)/(5)(15b-7)-(3b-9)=0
Domain of the equation: 5(15b-7)!=0We get rid of parentheses
b∈R
1/5(15b-7)-3b+9=0
We multiply all the terms by the denominator
-3b*5(15b-7)+9*5(15b-7)+1=0
Wy multiply elements
-15b^2(1+45b(1+1=0
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