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(5=3i)+(8-9i)
We move all terms to the left:
(5-(3i)+(8-9i))=0
We add all the numbers together, and all the variables
(5-3i+(-9i+8))=0
We calculate terms in parentheses: +(5-3i+(-9i+8)), so:We get rid of parentheses
5-3i+(-9i+8)
determiningTheFunctionDomain -3i+(-9i+8)+5
We get rid of parentheses
-3i-9i+8+5
We add all the numbers together, and all the variables
-12i+13
Back to the equation:
+(-12i+13)
-12i+13=0
We move all terms containing i to the left, all other terms to the right
-12i=-13
i=-13/-12
i=1+1/12
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