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(1)/(3)y-(1)/(2)=(1)/(6)y
We move all terms to the left:
(1)/(3)y-(1)/(2)-((1)/(6)y)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
Domain of the equation: 6y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
1/3y-(+1/6y)-1/2=0
We get rid of parentheses
1/3y-1/6y-1/2=0
We calculate fractions
(-108y^2)/72y^2+24y/72y^2+(-12y)/72y^2=0
We multiply all the terms by the denominator
(-108y^2)+24y+(-12y)=0
We get rid of parentheses
-108y^2+24y-12y=0
We add all the numbers together, and all the variables
-108y^2+12y=0
a = -108; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-108)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-108}=\frac{-24}{-216} =1/9 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-108}=\frac{0}{-216} =0 $
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