1/2(28+2x)=5(x2)

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Solution for 1/2(28+2x)=5(x2) equation: 



1/2(28+2x)=5(x2)

We move all terms to the left:

1/2(28+2x)-(5(x2))=0



Domain of the equation: 2(28+2x)!=0

x∈R



determiningTheFunctionDomain
1/2(28+2x)-5x2=0

We add all the numbers together, and all the variables

1/2(2x+28)-5x2=0

We add all the numbers together, and all the variables

-5x^2+1/2(2x+28)=0

We multiply all the terms by the denominator


-5x^2*2(2x+28)+1=0

Wy multiply elements

-10x^3(2+1=0

We do not support expression: x^3(2

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