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(1)/(3)x+(5)/(6)x=-3
We move all terms to the left:
(1)/(3)x+(5)/(6)x-(-3)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
1/3x+5/6x+3=0
We calculate fractions
6x/18x^2+15x/18x^2+3=0
We multiply all the terms by the denominator
6x+15x+3*18x^2=0
We add all the numbers together, and all the variables
21x+3*18x^2=0
Wy multiply elements
54x^2+21x=0
a = 54; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·54·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*54}=\frac{-42}{108} =-7/18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*54}=\frac{0}{108} =0 $
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