13-3(t-4)=6(t-7)+8

Solution for 13-3(t-4)=6(t-7)+8 equation:

13-3(t-4)=6(t-7)+8

We move all terms to the left:

13-3(t-4)-(6(t-7)+8)=0

We multiply parentheses

-3t-(6(t-7)+8)+12+13=0


We calculate terms in parentheses: -(6(t-7)+8), so:

6(t-7)+8

We multiply parentheses

6t-42+8

We add all the numbers together, and all the variables

6t-34

Back to the equation:

-(6t-34)


We add all the numbers together, and all the variables

-3t-(6t-34)+25=0

We get rid of parentheses

-3t-6t+34+25=0

We add all the numbers together, and all the variables

-9t+59=0

We move all terms containing t to the left, all other terms to the right

-9t=-59

t=-59/-9

t=6+5/9