(1)/(3)(t+6)-10=-3t+2

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Solution for (1)/(3)(t+6)-10=-3t+2 equation:



(1)/(3)(t+6)-10=-3t+2
We move all terms to the left:
(1)/(3)(t+6)-10-(-3t+2)=0
Domain of the equation: 3(t+6)!=0
t∈R
We get rid of parentheses
1/3(t+6)+3t-2-10=0
We multiply all the terms by the denominator
3t*3(t+6)-2*3(t+6)-10*3(t+6)+1=0
Wy multiply elements
9t^2(t-6t(t-30t(t+1=0

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