3(3m-2)=2(3m+3)+3

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Solution for 3(3m-2)=2(3m+3)+3 equation: 



3(3m-2)=2(3m+3)+3

We move all terms to the left:

3(3m-2)-(2(3m+3)+3)=0

We multiply parentheses

9m-(2(3m+3)+3)-6=0



We calculate terms in parentheses: -(2(3m+3)+3), so:

2(3m+3)+3

We multiply parentheses

6m+6+3

We add all the numbers together, and all the variables

6m+9

Back to the equation:

-(6m+9)



We get rid of parentheses

9m-6m-9-6=0

We add all the numbers together, and all the variables

3m-15=0

We move all terms containing m to the left, all other terms to the right

3m=15

m=15/3

m=5

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