(1)/(2)r+2((3)/(4)r-1)=(1)/(4)r+6

Solution for (1)/(2)r+2((3)/(4)r-1)=(1)/(4)r+6 equation:

(1)/(2)r+2((3)/(4)r-1)=(1)/(4)r+6

We move all terms to the left:

(1)/(2)r+2((3)/(4)r-1)-((1)/(4)r+6)=0


Domain of the equation: 2r!=0

r!=0/2

r!=0

r∈R



Domain of the equation: 4r-1)!=0

r∈R



Domain of the equation: 4r+6)!=0

r∈R


We multiply parentheses

1/2r+6r-(1/4r+6)-2=0

We get rid of parentheses

1/2r+6r-1/4r-6-2=0

We calculate fractions


6r+4r/8r^2+(-2r)/8r^2-6-2=0

We add all the numbers together, and all the variables

6r+4r/8r^2+(-2r)/8r^2-8=0

We multiply all the terms by the denominator


6r*8r^2+4r+(-2r)-8*8r^2=0

We add all the numbers together, and all the variables

4r+6r*8r^2+(-2r)-8*8r^2=0

Wy multiply elements

48r^3-64r^2+4r+(-2r)=0

We get rid of parentheses

48r^3-64r^2+4r-2r=0

We do not support erpression: r^3