1/3(y+5)+3=2/6(3y-3)

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Solution for 1/3(y+5)+3=2/6(3y-3) equation: 



1/3(y+5)+3=2/6(3y-3)

We move all terms to the left:

1/3(y+5)+3-(2/6(3y-3))=0



Domain of the equation: 3(y+5)!=0

y∈R





Domain of the equation: 6(3y-3))!=0

y∈R



We calculate fractions


(6y3/(3(y+5)*6(3y-3)))+(-6yy/(3(y+5)*6(3y-3)))+3=0



We calculate terms in parentheses: +(6y3/(3(y+5)*6(3y-3))), so:

6y3/(3(y+5)*6(3y-3))

We multiply all the terms by the denominator


6y3

We add all the numbers together, and all the variables

6y^3

We do not support eypression: y^3

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