(1)/(2)(6x+10)-4=-(1)/(4)(20x-8)

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Solution for (1)/(2)(6x+10)-4=-(1)/(4)(20x-8) equation:



(1)/(2)(6x+10)-4=-(1)/(4)(20x-8)
We move all terms to the left:
(1)/(2)(6x+10)-4-(-(1)/(4)(20x-8))=0
Domain of the equation: 2(6x+10)!=0
x∈R
Domain of the equation: 4(20x-8))!=0
x∈R
We calculate fractions
(4x2/(2(6x+10)*4(20x-8)))+(-(-2x6)/(2(6x+10)*4(20x-8)))-4=0
We calculate terms in parentheses: +(4x2/(2(6x+10)*4(20x-8))), so:
4x2/(2(6x+10)*4(20x-8))
We multiply all the terms by the denominator
4x2
We add all the numbers together, and all the variables
4x^2
Back to the equation:
+(4x^2)
We calculate terms in parentheses: +(-(-2x6)/(2(6x+10)*4(20x-8))), so:
-(-2x6)/(2(6x+10)*4(20x-8))
We add all the numbers together, and all the variables
-(-2x^6)/(2(6x+10)*4(20x-8))
We multiply all the terms by the denominator
-(-2x^6)
We do not support expression: x^6

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