(0.9256+.356x)(.356x)=0

Solution for (0.9256+.356x)(.356x)=0 equation:

(0.9256+.356x)(.356x)=0

We add all the numbers together, and all the variables

(.356x+0.9256)(+.356x)=0

We multiply parentheses ..

(+x^2+0.9256x)=0

We get rid of parentheses

x^2+0.9256x=0

a = 1; b = 0.9256; c = 0;
Δ = b2-4ac
Δ = 0.92562-4·1·0
Δ = 0.85673536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.9256)-\sqrt{0.85673536}}{2*1}=\frac{-0.9256-\sqrt{0.85673536}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.9256)+\sqrt{0.85673536}}{2*1}=\frac{-0.9256+\sqrt{0.85673536}}{2}
$