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(0.3x-0.3)(x-0.7)=0
We multiply parentheses ..
(+0x^2-0x-0.3x+0.21)=0
We get rid of parentheses
0x^2-0x-0.3x+0.21=0
We add all the numbers together, and all the variables
x^2-1.3x+0.21=0
a = 1; b = -1.3; c = +0.21;
Δ = b2-4ac
Δ = -1.32-4·1·0.21
Δ = 0.85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.3)-\sqrt{0.85}}{2*1}=\frac{1.3-\sqrt{0.85}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.3)+\sqrt{0.85}}{2*1}=\frac{1.3+\sqrt{0.85}}{2} $
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