(0.050+x)(0.040+x)=(0.045-x)(0.40-x)

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Solution for (0.050+x)(0.040+x)=(0.045-x)(0.40-x) equation: 



(0.050+x)(0.040+x)=(0.045-x)(0.40-x)

We move all terms to the left:

(0.050+x)(0.040+x)-((0.045-x)(0.40-x))=0

We add all the numbers together, and all the variables

(x+0.05)(x+0.04)-((-1x+0.045)(-1x+0.4))=0

We multiply parentheses ..

(+x^2+0.04x+0.05x+0.002)-((-1x+0.045)(-1x+0.4))=0



We calculate terms in parentheses: -((-1x+0.045)(-1x+0.4)), so:

(-1x+0.045)(-1x+0.4)

We multiply parentheses ..

(+x^2-0.4x-0.045x+0.018)

We get rid of parentheses

x^2-0.4x-0.045x+0.018

We add all the numbers together, and all the variables

x^2-0.445x+0.018

Back to the equation:

-(x^2-0.445x+0.018)



We get rid of parentheses

x^2-x^2+0.04x+0.05x+0.445x+0.002-0.018=0

We add all the numbers together, and all the variables

0.535x-0.016=0

We move all terms containing x to the left, all other terms to the right

0.535x=0.016

x=0.016/0.535

x=0.016/0.535

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