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(-x-25)(x-25)=36
We move all terms to the left:
(-x-25)(x-25)-(36)=0
We add all the numbers together, and all the variables
(-1x-25)(x-25)-36=0
We multiply parentheses ..
(-1x^2+25x-25x+625)-36=0
We get rid of parentheses
-1x^2+25x-25x+625-36=0
We add all the numbers together, and all the variables
-1x^2+589=0
a = -1; b = 0; c = +589;
Δ = b2-4ac
Δ = 02-4·(-1)·589
Δ = 2356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2356}=\sqrt{4*589}=\sqrt{4}*\sqrt{589}=2\sqrt{589}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{589}}{2*-1}=\frac{0-2\sqrt{589}}{-2} =-\frac{2\sqrt{589}}{-2} =-\frac{\sqrt{589}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{589}}{2*-1}=\frac{0+2\sqrt{589}}{-2} =\frac{2\sqrt{589}}{-2} =\frac{\sqrt{589}}{-1} $
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