(-w-5)(7w-1)=0

Solution for (-w-5)(7w-1)=0 equation:

(-w-5)(7w-1)=0

We add all the numbers together, and all the variables

(-1w-5)(7w-1)=0

We multiply parentheses ..

(-7w^2+w-35w+5)=0

We get rid of parentheses

-7w^2+w-35w+5=0

We add all the numbers together, and all the variables

-7w^2-34w+5=0

a = -7; b = -34; c = +5;
Δ = b2-4ac
Δ = -342-4·(-7)·5
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-36}{2*-7}=\frac{-2}{-14}
=1/7
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+36}{2*-7}=\frac{70}{-14}
=-5
$