(8v-7)(-6v+1)=0

Solution for (8v-7)(-6v+1)=0 equation:

(8v-7)(-6v+1)=0

We multiply parentheses ..

(-48v^2+8v+42v-7)=0

We get rid of parentheses

-48v^2+8v+42v-7=0

We add all the numbers together, and all the variables

-48v^2+50v-7=0

a = -48; b = 50; c = -7;
Δ = b2-4ac
Δ = 502-4·(-48)·(-7)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-34}{2*-48}=\frac{-84}{-96}
=7/8
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+34}{2*-48}=\frac{-16}{-96}
=1/6
$