(-8y+10)+(6y+2)=NY+12

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Solution for (-8y+10)+(6y+2)=NY+12 equation: 



(-8y+10)+(6y+2)=+12

We move all terms to the left:

(-8y+10)+(6y+2)-(+12)=0

We add all the numbers together, and all the variables

(-8y+10)+(6y+2)-12=0

We get rid of parentheses

-8y+6y+10+2-12=0

We add all the numbers together, and all the variables

-2y=0

y=0/-2

y=0

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