(2y+3)+(5y-1)=NY+2

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Solution for (2y+3)+(5y-1)=NY+2 equation: 



(2y+3)+(5y-1)=+2

We move all terms to the left:

(2y+3)+(5y-1)-(+2)=0

We add all the numbers together, and all the variables

(2y+3)+(5y-1)-2=0

We get rid of parentheses

2y+5y+3-1-2=0

We add all the numbers together, and all the variables

7y=0

y=0/7

y=0

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