(-4-2x)x+10-7=5

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Solution for (-4-2x)x+10-7=5 equation: 



(-4-2x)x+10-7=5

We move all terms to the left:

(-4-2x)x+10-7-(5)=0

We add all the numbers together, and all the variables

(-2x-4)x+10-7-5=0

We add all the numbers together, and all the variables

(-2x-4)x-2=0

We multiply parentheses

-2x^2-4x-2=0

a = -2; b = -4; c = -2;
Δ = b2-4ac
Δ = -42-4·(-2)·(-2)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{4}{-4}=-1$

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