40-2x=(2/3)x

Solution for 40-2x=(2/3)x equation:

40-2x=(2/3)x

We move all terms to the left:

40-2x-((2/3)x)=0


Domain of the equation: 3)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-2x-((+2/3)x)+40=0

We multiply all the terms by the denominator


-2x*3)x)-((+40*3)x)+2=0

We add all the numbers together, and all the variables

-2x*3)x)-(120x)+2=0

We add all the numbers together, and all the variables

-2x*3)x)-120x+2=0

Wy multiply elements

-6x^2=0

a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-12}=0$