(-4(n+3)=2(1-3n))

Solution for (-4(n+3)=2(1-3n)) equation:

(-4(n+3)=2(1-3n))

We move all terms to the left:

(-4(n+3)-(2(1-3n)))=0

We add all the numbers together, and all the variables

(-4(n+3)-(2(-3n+1)))=0


We calculate terms in parentheses: +(-4(n+3)-(2(-3n+1))), so:

-4(n+3)-(2(-3n+1))

We multiply parentheses

-4n-(2(-3n+1))-12


We calculate terms in parentheses: -(2(-3n+1)), so:

2(-3n+1)

We multiply parentheses

-6n+2

Back to the equation:

-(-6n+2)


We get rid of parentheses

-4n+6n-2-12

We add all the numbers together, and all the variables

2n-14

Back to the equation:

+(2n-14)


We get rid of parentheses

2n-14=0

We move all terms containing n to the left, all other terms to the right

2n=14

n=14/2

n=7