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(-3x+7)(-5x+2)=0
We multiply parentheses ..
(+15x^2-6x-35x+14)=0
We get rid of parentheses
15x^2-6x-35x+14=0
We add all the numbers together, and all the variables
15x^2-41x+14=0
a = 15; b = -41; c = +14;
Δ = b2-4ac
Δ = -412-4·15·14
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-29}{2*15}=\frac{12}{30} =2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+29}{2*15}=\frac{70}{30} =2+1/3 $
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