(-3+3i)(-2+2i)=

Solution for (-3+3i)(-2+2i)= equation:

Simplifying
(-3 + 3i)(-2 + 2i) = 0

Multiply (-3 + 3i) * (-2 + 2i)
(-3(-2 + 2i) + 3i * (-2 + 2i)) = 0
((-2 * -3 + 2i * -3) + 3i * (-2 + 2i)) = 0
((6 + -6i) + 3i * (-2 + 2i)) = 0
(6 + -6i + (-2 * 3i + 2i * 3i)) = 0
(6 + -6i + (-6i + 6i2)) = 0

Combine like terms: -6i + -6i = -12i
(6 + -12i + 6i2) = 0

Solving
6 + -12i + 6i2 = 0

Solving for variable 'i'.

Factor out the Greatest Common Factor (GCF), '6'.
6(1 + -2i + i2) = 0

Factor a trinomial.
6((1 + -1i)(1 + -1i)) = 0

Ignore the factor 6.
Subproblem 1
Set the factor '(1 + -1i)' equal to zero and attempt to solve:

Simplifying
1 + -1i = 0

Solving
1 + -1i = 0

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1i = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1i = 0 + -1
-1i = 0 + -1

Combine like terms: 0 + -1 = -1
-1i = -1

Divide each side by '-1'.
i = 1

Simplifying
i = 1
Subproblem 2
Set the factor '(1 + -1i)' equal to zero and attempt to solve:

Simplifying
1 + -1i = 0

Solving
1 + -1i = 0

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1i = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1i = 0 + -1
-1i = 0 + -1

Combine like terms: 0 + -1 = -1
-1i = -1

Divide each side by '-1'.
i = 1

Simplifying
i = 1
Solution
i = {1, 1}