(-2x+9)/5=(3x-4)/2

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Solution for (-2x+9)/5=(3x-4)/2 equation: 



(-2x+9)/5=(3x-4)/2

We move all terms to the left:

(-2x+9)/5-((3x-4)/2)=0

We calculate fractions


(-2x)/()+(-((3x-4)*5)/()=0



We calculate terms in parentheses: +(-((3x-4)*5)/(), so:

-((3x-4)*5)/(

We multiply all the terms by the denominator


-((3x-4)*5)



We calculate terms in parentheses: -((3x-4)*5), so:

(3x-4)*5

We multiply parentheses

15x-20

Back to the equation:

-(15x-20)



We get rid of parentheses

-15x+20

Back to the equation:

+(-15x+20)



We get rid of parentheses

(-2x)/()-15x+20=0

We multiply all the terms by the denominator


(-2x)-15x*()+20*()=0

We add all the numbers together, and all the variables

(-2x)-15x*()=0

We get rid of parentheses

-2x-15x*()=0

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