(4k+2)(k+1)=k

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Solution for (4k+2)(k+1)=k equation: 



(4k+2)(k+1)=k

We move all terms to the left:

(4k+2)(k+1)-(k)=0

We add all the numbers together, and all the variables

-1k+(4k+2)(k+1)=0

We multiply parentheses ..

(+4k^2+4k+2k+2)-1k=0

We get rid of parentheses

4k^2+4k+2k-1k+2=0

We add all the numbers together, and all the variables

4k^2+5k+2=0

a = 4; b = 5; c = +2;
Δ = b2-4ac
Δ = 52-4·4·2
Δ = -7
Delta is less than zero, so there is no solution for the equation

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