(-21/2)p=-3

Solution for (-21/2)p=-3 equation:

(-21/2)p=-3

We move all terms to the left:

(-21/2)p-(-3)=0


Domain of the equation: 2)p!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

(-21/2)p+3=0

We multiply parentheses

-21p^2+3=0

a = -21; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-21)·3
Δ = 252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{252}=\sqrt{36*7}=\sqrt{36}*\sqrt{7}=6\sqrt{7}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{7}}{2*-21}=\frac{0-6\sqrt{7}}{-42}
=-\frac{6\sqrt{7}}{-42}
=-\frac{\sqrt{7}}{-7}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{7}}{2*-21}=\frac{0+6\sqrt{7}}{-42}
=\frac{6\sqrt{7}}{-42}
=\frac{\sqrt{7}}{-7}
$