4(1+2n)=2(6n+6)

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Solution for 4(1+2n)=2(6n+6) equation: 



4(1+2n)=2(6n+6)

We move all terms to the left:

4(1+2n)-(2(6n+6))=0

We add all the numbers together, and all the variables

4(2n+1)-(2(6n+6))=0

We multiply parentheses

8n-(2(6n+6))+4=0



We calculate terms in parentheses: -(2(6n+6)), so:

2(6n+6)

We multiply parentheses

12n+12

Back to the equation:

-(12n+12)



We get rid of parentheses

8n-12n-12+4=0

We add all the numbers together, and all the variables

-4n-8=0

We move all terms containing n to the left, all other terms to the right

-4n=8

n=8/-4

n=-2

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