(-16k-4)-(-24k+12)=3(8-k)-8

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Solution for (-16k-4)-(-24k+12)=3(8-k)-8 equation: 



(-16k-4)-(-24k+12)=3(8-k)-8

We move all terms to the left:

(-16k-4)-(-24k+12)-(3(8-k)-8)=0

We add all the numbers together, and all the variables

(-16k-4)-(-24k+12)-(3(-1k+8)-8)=0

We get rid of parentheses

-16k+24k-(3(-1k+8)-8)-4-12=0



We calculate terms in parentheses: -(3(-1k+8)-8), so:

3(-1k+8)-8

We multiply parentheses

-3k+24-8

We add all the numbers together, and all the variables

-3k+16

Back to the equation:

-(-3k+16)



We add all the numbers together, and all the variables

8k-(-3k+16)-16=0

We get rid of parentheses

8k+3k-16-16=0

We add all the numbers together, and all the variables

11k-32=0

We move all terms containing k to the left, all other terms to the right

11k=32

k=32/11

k=2+10/11

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