12y=10-2y-(y-5)

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Solution for 12y=10-2y-(y-5) equation: 



12y=10-2y-(y-5)

We move all terms to the left:

12y-(10-2y-(y-5))=0



We calculate terms in parentheses: -(10-2y-(y-5)), so:

10-2y-(y-5)

determiningTheFunctionDomain
-2y-(y-5)+10

We get rid of parentheses

-2y-y+5+10

We add all the numbers together, and all the variables

-3y+15

Back to the equation:

-(-3y+15)



We get rid of parentheses

12y+3y-15=0

We add all the numbers together, and all the variables

15y-15=0

We move all terms containing y to the left, all other terms to the right

15y=15

y=15/15

y=1

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