(-12-6x)=(10x+20)

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Solution for (-12-6x)=(10x+20) equation: 



(-12-6x)=(10x+20)

We move all terms to the left:

(-12-6x)-((10x+20))=0

We add all the numbers together, and all the variables

(-6x-12)-((10x+20))=0

We get rid of parentheses

-6x-((10x+20))-12=0



We calculate terms in parentheses: -((10x+20)), so:

(10x+20)

We get rid of parentheses

10x+20

Back to the equation:

-(10x+20)



We get rid of parentheses

-6x-10x-20-12=0

We add all the numbers together, and all the variables

-16x-32=0

We move all terms containing x to the left, all other terms to the right

-16x=32

x=32/-16

x=-2

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