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2(3x+5)=5(2x-4)-5x
We move all terms to the left:
2(3x+5)-(5(2x-4)-5x)=0
We multiply parentheses
6x-(5(2x-4)-5x)+10=0
We calculate terms in parentheses: -(5(2x-4)-5x), so:We get rid of parentheses
5(2x-4)-5x
We add all the numbers together, and all the variables
-5x+5(2x-4)
We multiply parentheses
-5x+10x-20
We add all the numbers together, and all the variables
5x-20
Back to the equation:
-(5x-20)
6x-5x+20+10=0
We add all the numbers together, and all the variables
x+30=0
We move all terms containing x to the left, all other terms to the right
x=-30
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