(-12-2x)(-12-2x)=0

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Solution for (-12-2x)(-12-2x)=0 equation: 



(-12-2x)(-12-2x)=0

We add all the numbers together, and all the variables

(-2x-12)(-2x-12)=0

We multiply parentheses ..

(+4x^2+24x+24x+144)=0

We get rid of parentheses

4x^2+24x+24x+144=0

We add all the numbers together, and all the variables

4x^2+48x+144=0

a = 4; b = 48; c = +144;
Δ = b2-4ac
Δ = 482-4·4·144
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-48}{8}=-6$

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