(-11/4)p+23P=7

Solution for (-11/4)p+23P=7 equation:

(-11/4)p+23=7

We move all terms to the left:

(-11/4)p+23-(7)=0


Domain of the equation: 4)p!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

(-11/4)p+16=0

We multiply parentheses

-11p^2+16=0

a = -11; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·(-11)·16
Δ = 704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{704}=\sqrt{64*11}=\sqrt{64}*\sqrt{11}=8\sqrt{11}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{11}}{2*-11}=\frac{0-8\sqrt{11}}{-22}
=-\frac{8\sqrt{11}}{-22}
=-\frac{4\sqrt{11}}{-11}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{11}}{2*-11}=\frac{0+8\sqrt{11}}{-22}
=\frac{8\sqrt{11}}{-22}
=\frac{4\sqrt{11}}{-11}
$