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3(10x-5)=5(5x+1)
We move all terms to the left:
3(10x-5)-(5(5x+1))=0
We multiply parentheses
30x-(5(5x+1))-15=0
We calculate terms in parentheses: -(5(5x+1)), so:We get rid of parentheses
5(5x+1)
We multiply parentheses
25x+5
Back to the equation:
-(25x+5)
30x-25x-5-15=0
We add all the numbers together, and all the variables
5x-20=0
We move all terms containing x to the left, all other terms to the right
5x=20
x=20/5
x=4
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