(-11+6x)(8x+2)=0

Solution for (-11+6x)(8x+2)=0 equation:

(-11+6x)(8x+2)=0

We add all the numbers together, and all the variables

(6x-11)(8x+2)=0

We multiply parentheses ..

(+48x^2+12x-88x-22)=0

We get rid of parentheses

48x^2+12x-88x-22=0

We add all the numbers together, and all the variables

48x^2-76x-22=0

a = 48; b = -76; c = -22;
Δ = b2-4ac
Δ = -762-4·48·(-22)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-100}{2*48}=\frac{-24}{96}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+100}{2*48}=\frac{176}{96}
=1+5/6
$